测试源码与对应的反汇编代码
考虑如下一段c++源码 1
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class Base {
public:
virtual void show() {
std::cout << "Base class show function" << std::endl;
}
};
class Derived : public Base {
public:
void show() override {
std::cout << "Derived class show function" << std::endl;
}
};
int main() {
Base* basePtr = new Base();
Base* derivedPtr = new Derived();
basePtr->show();
derivedPtr->show();
delete basePtr;
delete derivedPtr;
return 0;
}
